DAG(Directed Acyclic Graph)의 토폴로지 정렬은 정점 u가 순서에서 v 앞에 오는 모든 방향 모서리 uv에 대해 정점의 선형 정렬입니다. 그래프가 DAG가 아닌 경우 그래프에 대한 Topological Sorting이 불가능합니다.
함수 및 의사코드
Begin function topologicalSort(): a) Mark the current node as visited. b) Recur for all the vertices adjacent to this vertex. c) Push current vertex to stack which stores result. End Begin function topoSort() which uses recursive topological sort() function: a) Mark all the vertices which are not visited. b) Call the function topologicalSort(). c) Print the content. End
예시
#include<iostream> #include <list> #include <stack> using namespace std; class G { int n; list<int> *adj; //declaration of functions void topologicalSort(int v, bool visited[], stack<int> &Stack); public: G(int n); //constructor void addEd(int v, int w); void topoSort(); }; G::G(int n) { this->n = n; adj = new list<int> [n]; } void G::addEd(int v, int w) // add the edges to the graph. { adj[v].push_back(w); //add w to v’s list } void G::topologicalSort(int v, bool visited[], stack<int> &Stack) { visited[v] = true; //mark current node as visited list<int>::iterator i; //Recur for all the vertices adjacent to this vertex. for (i = adj[v].begin(); i != adj[v].end(); ++i) if (!visited[*i]) topologicalSort(*i, visited, Stack); Stack.push(v); } void G::topoSort() { stack<int> Stack; bool *visited = new bool[n]; //Mark all the vertices which are not visited. for (int i = 0; i < n; i++) visited[i] = false; for (int i = 0; i < n; i++) if (visited[i] == false) //Call the function topologicalSort(). topologicalSort(i, visited, Stack); while (Stack.empty() == false) { cout << Stack.top() << " "; //print the element Stack.pop(); } } int main() { G g(6); g.addEd(4, 2); g.addEd(5, 1); g.addEd(4, 0); g.addEd(3, 1); g.addEd(1, 3); g.addEd(3, 2); cout << " Topological Sort of the given graph \n"; g.topoSort(); return 0; }
출력
Topological Sort of the given graph 5 4 1 3 2 0