같은 나이의 학생 빈도를 계산하는 MySQL 쿼리는 무엇입니까?

이를 위해 GROUP BY와 함께 COUNT(*)를 사용할 수 있습니다. 먼저 테이블을 생성하겠습니다 -

mysql> create table DemoTable
   (
   StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   StudentAge int
   );
Query OK, 0 rows affected (0.59 sec)

삽입 명령을 사용하여 테이블에 레코드 삽입 -

mysql> insert into DemoTable(StudentAge) values(16);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable(StudentAge) values(17);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable(StudentAge) values(18);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable(StudentAge) values(17);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable(StudentAge) values(17);
Query OK, 1 row affected (0.23 sec)
mysql> insert into DemoTable(StudentAge) values(17);
Query OK, 1 row affected (0.08 sec)
mysql> insert into DemoTable(StudentAge) values(18);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable(StudentAge) values(18);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable(StudentAge) values(19);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable(StudentAge) values(19);
Query OK, 1 row affected (0.07 sec)
mysql> insert into DemoTable(StudentAge) values(16);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable(StudentAge) values(16);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(StudentAge) values(15);
Query OK, 1 row affected (0.16 sec)

select 문을 사용하여 테이블의 모든 레코드 표시 -

mysql> select * from DemoTable;

이것은 다음과 같은 출력을 생성합니다 -

+-----------+------------+
| StudentId | StudentAge |
+-----------+------------+
| 1         | 16         |
| 2         | 17         |
| 3         | 18         |
| 4         | 17         |
| 5         | 17         |
| 6         | 17         |
| 7         | 18         |
| 8         | 18         |
| 9         | 19         |
| 10        | 19         |
| 11        | 16         |
| 12        | 16         |
| 13        | 15         |
+-----------+------------+
13 rows in set (0.00 sec)

다음은 빈도를 계산하는 쿼리입니다 -

mysql> select StudentAge,count(*) AS `AgeFrequency` from DemoTable group by StudentAge;

이것은 다음과 같은 출력을 생성합니다 -

+------------+--------------+
| StudentAge | AgeFrequency |
+------------+--------------+
| 16         | 3            |
| 17         | 4            |
| 18         | 3            |
| 19         | 2            |
| 15         | 1            |
+------------+--------------+
5 rows in set (0.05 sec)