HybridDictionary에서 모든 항목을 제거하려면 코드는 다음과 같습니다. -
예시
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
HybridDictionary dict1 = new HybridDictionary();
dict1.Add("A", "Books");
dict1.Add("B", "Electronics");
dict1.Add("C", "Smart Wearables");
dict1.Add("D", "Pet Supplies");
dict1.Add("E", "Clothing");
dict1.Add("F", "Footwear");
Console.WriteLine("HybridDictionary1 elements...");
foreach(DictionaryEntry d in dict1){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of Key/value pairs in Dictionary1 = "+dict1.Count);
HybridDictionary dict2 = new HybridDictionary();
dict2.Add("1", "One");
dict2.Add("2", "Two");
dict2.Add("3", "Three");
dict2.Add("4", "Four");
dict2.Add("5", "Five");
dict2.Add("6", "Six");
Console.WriteLine("\nHybridDictionary2 elements...");
foreach(DictionaryEntry d in dict2){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of Key/value pairs in Dictionary2 = "+dict1.Count);
dict2.Clear();
Console.WriteLine("Count of Key/value pairs in Dictionary2 (Updated) = "+dict2.Count);
}
} 출력
이것은 다음과 같은 출력을 생성합니다 -
HybridDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing F Footwear Count of Key/value pairs in Dictionary1 = 6 HybridDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of Key/value pairs in Dictionary2 = 6 Count of Key/value pairs in Dictionary2 (Updated) = 0
예시
다른 예를 보겠습니다 -
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
HybridDictionary dict = new HybridDictionary();
dict.Add("One", "Accessories");
dict.Add("Two", "Pet Supplies");
Console.WriteLine("HybridDictionary elements...");
foreach(DictionaryEntry d in dict){
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of Key/value pairs in Dictionary = "+dict.Count);
}
} 출력
이것은 다음과 같은 출력을 생성합니다 -
HybridDictionary elements... One Accessories Two Pet Supplies Count of Key/value pairs in Dictionary = 2