주어진 특정 케이스에 대해 N개의 문자 시퀀스를 생성하는 C++ 프로그램

이것은 주어진 특정 경우에 대해 N개의 문자 시퀀스를 생성하는 C++ 프로그램입니다.

알고리즘

Begin
   function GenerateSequence() generate a Sequence of N Characters for a Given Specific Case:
      Use rand() for generating random indexes.
      Store the first character directly into the sequence.
      If that sequence is used earlier, then it discards that and generates random index again.
End

예시

#include<iostream>
#include<stdlib.h>
#include<string.h>
using namespace std;
void GenerateSequence(char string[], int n, int l, char *sequence)
{
   int i, j=0, k,in;
   for(i = 0; i < n; i++) {
      //store first character directly into sequence
      if(j == 0)
         sequence[j++] = string[rand()%l];
      else {
         h:
         in = rand()%l;
         for(k = 0; k < j; k++) {
            if(string[in] == sequence[k])
               goto h;
         }
         sequence[j++] = string[in];
      }
   }
   sequence[j] = '\0'; //end the sequence with null character
}
int main() {
   int n, m, l, i;
   char string[100];
   cout<<"Enter the original string: ";
   cin>>string;
   cout<<"\nEnter the number of strings to be generated from the Base string: ";
   cin>>n;
   cout<<"\nEnter the length of each string to be generated: ";
   cin>>m;
   l = strlen(string);
   for(i = 0; i < n; i++) {
      char sequence[m];
      GenerateSequence(string, m, l, sequence);
      cout<<"\nSequence "<<i+1<<": "<<sequence;
   }
   return 0;
}

출력

Enter the original string: tutorialspoint
Enter the number of strings to be generated from the Base string: 7
Enter the length of each string to be generated: 6
Sequence 1: tuanol
Sequence 2: itlurp
Sequence 3: tonaiu
Sequence 4: untlri
Sequence 5: liorpt
Sequence 6: liusto
Sequence 7: luisot