Hashtable에서 지정된 키를 가진 요소를 제거하려면 코드는 다음과 같습니다. -
예시
using System; using System.Collections; public class Demo { public static void Main(){ Hashtable hash = new Hashtable(10); hash.Add("1", "A"); hash.Add("2", "B"); hash.Add("3", "C"); hash.Add("4", "D"); hash.Add("5","E"); hash.Add("6", "F"); hash.Add("7", "G"); hash.Add("8","H"); hash.Add("9", "I"); hash.Add("10", "J"); Console.WriteLine("Hashtable Key and Value pairs..."); foreach(DictionaryEntry entry in hash){ Console.WriteLine("{0} and {1} ", entry.Key, entry.Value); } Console.WriteLine("Is the Hashtable having fixed size? = "+hash.IsFixedSize); Console.WriteLine("Count of entries in Hashtable = "+ hash.Count); hash.Remove("5"); Console.WriteLine("Count of entries in Hashtable (updated) = "+hash.Count); } }
출력
이것은 다음과 같은 출력을 생성합니다 -
Hashtable Key and Value pairs... 10 and J 1 and A 2 and B 3 and C 4 and D 5 and E 6 and F 7 and G 8 and H 9 and I Is the Hashtable having fixed size? = False Count of entries in Hashtable = 10 Count of entries in Hashtable (updated) = 9
예시
다른 예를 살펴보겠습니다 -
using System; using System.Collections; public class Demo { public static void Main(){ Hashtable hash = new Hashtable(10); hash.Add("One", "Marketing"); hash.Add("Two", "Operations"); hash.Add("Three", "Finance"); hash.Add("Four", "IT"); hash.Add("Five","Sales"); hash.Add("Six", "Purchase"); Console.WriteLine("Hashtable Key and Value pairs..."); foreach(DictionaryEntry entry in hash){ Console.WriteLine("{0} and {1} ", entry.Key, entry.Value); } Console.WriteLine("Count of entries in Hashtable = "+ hash.Count); hash.Remove("Two"); hash.Remove("Three"); hash.Remove("Four"); Console.WriteLine("Count of entries in Hashtable (updated) = "+hash.Count); } }
출력
이것은 다음과 같은 출력을 생성합니다 -
Hashtable Key and Value pairs... One and Marketing Five and Sales Three and Finance Two and Operations Four and IT Six and Purchase Count of entries in Hashtable = 6 Count of entries in Hashtable (updated) = 3